i 想向青少年提出内容,但与他们有关系。
cout << &text[0] << endl;
似乎产生其ule,这里究竟是什么错了?
感谢
您需要转换为<代码>,避免与流体印刷的,并且需要一个安全的操作者地址,该地址被超载的<代码>&-operators混淆。 换言之:
std::cout << static_cast<void*>(std::addressof(text[0])) << std::endl;
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Update: Note that this code gives you the static address of the operand. If you want to pass a base reference of a polymorphic object, you should use dynamic_cast<void*>(x) instead, but this works only for polymorphic objects (i.e. those with virtual functions), and it gives you the address of the actual, dynamic object.
就像:
printf("%p",text);
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