Question

我的java申请装上XML档案,然后用XML。

在我创建SAXBuilder之前,我想做的是搜查/替代文件。我怎么能够记住(不必写到档案中)?

这里是我的法典,我设想进行搜查/替代:

private String xmlFile = "D:\mycomputer\extract.xml";
File myXMLFile = new File(xmlFile);

// TODO
// REPLACE ALL "<content>" in xmlFile with "<content><![CDATA["
// REPLACE ALL "</content>" with "]]></content>"

SAXBuilder builder =  new SAXBuilder("org.apache.xerces.parsers.SAXParser");

document = builder.build(new File(myXMLFile));

Answer 1

Read the file into memory, do the search/replace, and use the SAXBuilder(StringReader) method.

Answer 2

You can first read file to string with apache commons io and then change the input source for the SaxBuilder as in the following code snippet:

String fileStr = FileUtils.readFileToString(myXMLFile);
fileStr = fileStr.replaceAll("<content>","<content><![CDATA[");
fileStr = fileStr.replaceAll("</content>","]]></content>");
SAXBuilder builder =  new SAXBuilder("org.apache.xerces.parsers.SAXParser");
document = builder.build(new ByteArrayInputStream(fileStr.getBytes()));

Answer 3

你回答了问题,将整个档案翻译成“斯特林堡”,代之以,然后打电话给“斯特凡”。

The string can be passed to SAXBuilder using StringReader:

StringBuilder sb = new StringBuilder ();
loadFIleContent (filePath, sb);
document = builder.build (new StringReader (sb.toString ()));

P.S.: follow up to theglauber s answer:

如果档案确实大(~100Mb),那么将它完全读到记忆中,并将其划入OM树是不切实际的。在这种情况下,你应考虑使用SAXParser,取代档案。

Answer 4

根据这些档案的大小,或者读到“Sting”,你在记忆中进行更换,并从“Sting”建造“XML”,或者在读到档案时铺开新的通道,取而代之和产出,然后从“Stemo”的输出中进行XML的建设。

(我建议 par平和修改XML树或使用XML过滤器,但怀疑你想要做这种扼杀性的替换,因为你的档案内容不正确。)

友情链接