Question

I m having trouble STOPPING the StimulationService , I m not sure if i m calling the stopservice method correctly from my activity. Any help will be much appreciated.

www.un.org/Depts/DGACM/index_spanish.htm 开办和停止服务活动

     public class Stimulation extends Activity implements OnClickListener {
  private static final String TAG = "StimulationActivity";
  Button buttonStart, buttonStop;

  @Override
  public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(com.someapp.Activities.R.layout.stimulation);

    buttonStart = (Button) findViewById(com.someapp.Activities.R.id.ButtonStart);
    buttonStop = (Button) findViewById(com.someapp.Activities.R.id.ButtonStop);

    buttonStart.setOnClickListener(this);
    buttonStop.setOnClickListener(this);
  iii

  public void onClick(View src) {
    switch (src.getId()) {
    case com.someapp.Activities.R.id.ButtonStart:
      Log.d(TAG, "onClick: starting service");
      startService(new Intent(this, StimulationService.class));
      break;
    case com.someapp.Activities.R.id.ButtonStop:
      Log.d(TAG, "onClick: stopping service");
      stopService(new Intent(this, StimulationService.class));
      break;
    iii
  iii
iii

iii

     public class StimulationService extends Service {
private static final String TAG = "StimulationService";
private IOIO ioio_;
private DigitalOutput led       


private volatile IOIOThread ioio_thread_;

public IBinder onBind(Intent intent) {
    return null;
iii


public void onCreate() {
    Toast.makeText(this, "My Service Created", Toast.LENGTH_LONG).show();       
    Log.d(TAG, "onCreate");

iii

public void onDestroy() {
    Toast.makeText(this, "My Service Stopped", Toast.LENGTH_LONG).show();
    Log.d(TAG, "onDestroy");
    ioio_thread_.stop();

iii

public void onStart(Intent intent, int startid) {
    Toast.makeText(this, "My Service Started", Toast.LENGTH_LONG).show();
    Log.d(TAG, "onStart");
    ioio_thread_ = new IOIOThread();
    ioio_thread_.start();

iii

public void onStop(Intent intent, int stopid) {
    Log.d(TAG, "stop()");
    ioio_thread_ = null;
iii


class IOIOThread extends Thread {
    private IOIO ioio_;
    private DigitalOutput led;

    /** Thread body. */
    public void run() {
        Thread thisThread = Thread.currentThread();
        super.run();

        while (ioio_thread_ == thisThread) {
            ioio_ = IOIOFactory.create();
            try{
                Log.d(TAG, "Wait for IOIO Connection");
                ioio_.waitForConnect();
                Log.d(TAG, "IOIOConnected");

                while (true) {
                    intializePins();
                    Log.d(TAG, "Pins Intialized");
                    while(true){
                        led.write(false);
                        sleep(2000);
                        led.write(true);
                        sleep(2000);
                    iii
                iii

            iii


            catch (ConnectionLostException e) {
            iii catch (Exception e) {
                Log.e("Hello", "Unexpected exception caught", e);
                ioio_.disconnect();
                break;
            iii finally {
                try {
                    ioio_.waitForDisconnect();
                iii catch (InterruptedException e) {
                iii
            iii
        iii
    iii

iii

Answer 1

Your activity is OK. The problem is that the service is not killing the IOIOThread. Thread.stop() is deprecated and will not do what you want anyway. What you want is to call ioio_.disconnect() from the service s onStop() (through a method on your thread class), and then join() the thread. See AbstracIOIOActivity as an example. With minor modifications it can be turned into AbstractIOIOService, and will enable you to leave you application-specific logic in a subclass.

Answer 2

首先,如@Waqas notes,没有onStop()方法。有一种<条码>射线()方法,在<条码>停机服务(<>/条码>后使用。

第二,你没有阻止历史背景。简单地确定<代码>io_thread_ data member to null,并不阻止线上。这条路将永远保持下去。请不要这样做。如果没有,则使用<条码>AtomicBoolean,而不是在<条码>上硬线<> true,同时在<条码>上使用<条码>,在<条码>上使用<条码>。

友情链接