Question

我的输出文本有相当多的内容,我需要删除两种模式之间的所有线,但保持模式匹配。

这些档案含糊地看着以下产出。

 TEST #1          
      coef1 |   48.36895    3.32013    14.57   0.000     41.86141    54.87649
      coef2 |  -50.08894   10.47335    -4.78   0.000    -70.61697   -29.56092
            |
  indicator |
         0  |   .6647992   2.646627     0.25   0.802     -4.55925    5.888849
         1  |   2.118701   5.225777     0.41   0.686     -8.19621    12.43361
            |
       year |
         2  |  -.4324005   2.231387    -0.19   0.847    -4.836829    3.972028
         3  |   -.362762    1.97184    -0.18   0.854    -4.254882    3.529358
            |
      _cons |   16.95753   6.342342     2.67   0.008     4.526383    29.38869
 TEST #2          
        coef2 |   48.36895    3.32013    14.57   0.000     41.86141    54.87649
        coef3 |  -50.08894   10.47335    -4.78   0.000    -70.61697   -29.56092
              |
         year |
           4  |   .6647992   2.646627     0.25   0.802     -4.55925    5.888849
           5  |   2.118701   5.225777     0.41   0.686     -8.19621    12.43361
              |
     idnumber |
           6  |  -.4324005   2.231387    -0.19   0.847    -4.836829    3.972028
           7  |   -.362762    1.97184    -0.18   0.854    -4.254882    3.529358
              |
        _cons |   16.95753   6.342342     2.67   0.008     4.526383    29.38869

我需要得出以下产出,删除“年”和“年”之间的所有线,但我需要保留从“条”开始的线。预期成果如下:

 TEST #1          
      coef1 |   48.36895    3.32013    14.57   0.000     41.86141    54.87649
      coef2 |  -50.08894   10.47335    -4.78   0.000    -70.61697   -29.56092
            |
  indicator |
         0  |   .6647992   2.646627     0.25   0.802     -4.55925    5.888849
         1  |   2.118701   5.225777     0.41   0.686     -8.19621    12.43361
            |
       year |
      _cons |   16.95753   6.342342     2.67   0.008     4.526383    29.38869
 TEST #2          
        coef2 |   48.36895    3.32013    14.57   0.000     41.86141    54.87649
        coef3 |  -50.08894   10.47335    -4.78   0.000    -70.61697   -29.56092
              |
         year |
        _cons |   16.95753   6.342342     2.67   0.008     4.526383    29.38869

我写了以下文字(在文件十下):

sed  /^ +year/,/^ +_cons/{/^ +year/!{/^ +_cons/!d}}  input.txt >output.txt

但我有以下错误:

sed: 1: "/^ +year/,/^ +_cons/{/^ ...": extra characters at the end of d command

我不敢肯定这种做法是否正确,因为我似乎无法执行。这里甚至合适吗?

最后一项说明是,我需要这一文字在相对通用的“团结”装置上工作。我不得不向那些必须在非常基本的AIX(我认为)装置下执行这一规定的人发出这一信息。在电子邮件上安装时,我不会 per,也不能 p。

Answer 1

在<代码>d后添加一个半殖民地,以表明指挥工作已经结束。 (GNUsed——唯一sed 我有手脚检验——是否要求这样做,但也许还有另一个<条码>:?

此外,如果你需要支持<代码><>ed的多种实施,那么你可以使用<代码>+,即“一个或多个”:它不是标准,也不是所有执行支持。您可使用<代码>{1,},但这种编号只是粗略的。页: 1

因此:

sed  /^ * year/,/^ * _cons/{/^ * year/!{/^ * _cons/!d;}}  input.txt >output.txt

(经测试,但仅使用GNUsed ,而不是OS X,当然不是AIX, sorry)。)

Answer 2

这应当做到:

awk  /year/{print; getline; while($0!~/_cons/) {getline}}1  INPUT_FILE

<>>>

awk  /_cons/{print;f=0;next}/year/{f=1;print;next}f{next}1  INPUT_FILE

Following is the Output with your input-data file:

[jaypal:~/Temp] awk  /year/{print; getline; while($0!~/_cons/) {getline}}1  file
TEST #1          
      coef1 |   48.36895    3.32013    14.57   0.000     41.86141    54.87649
      coef2 |  -50.08894   10.47335    -4.78   0.000    -70.61697   -29.56092
            |
  indicator |
         0  |   .6647992   2.646627     0.25   0.802     -4.55925    5.888849
         1  |   2.118701   5.225777     0.41   0.686     -8.19621    12.43361
            |
       year |
      _cons |   16.95753   6.342342     2.67   0.008     4.526383    29.38869
 TEST #2          
        coef2 |   48.36895    3.32013    14.57   0.000     41.86141    54.87649
        coef3 |  -50.08894   10.47335    -4.78   0.000    -70.61697   -29.56092
              |
         year |
        _cons |   16.95753   6.342342     2.67   0.008     4.526383    29.38869

Test2:

[jaypal:~/Temp] awk  /_cons/{print;f=0;next}/year/{f=1;print;next}f{next}1  file
TEST #1          
      coef1 |   48.36895    3.32013    14.57   0.000     41.86141    54.87649
      coef2 |  -50.08894   10.47335    -4.78   0.000    -70.61697   -29.56092
            |
  indicator |
         0  |   .6647992   2.646627     0.25   0.802     -4.55925    5.888849
         1  |   2.118701   5.225777     0.41   0.686     -8.19621    12.43361
            |
       year |
      _cons |   16.95753   6.342342     2.67   0.008     4.526383    29.38869
TEST #2          
      coef2 |   48.36895    3.32013    14.57   0.000     41.86141    54.87649
      coef3 |  -50.08894   10.47335    -4.78   0.000    -70.61697   -29.56092
            |
       year |
      _cons |   16.95753   6.342342     2.67   0.008     4.526383    29.38869

Answer 3

这或许有助于你:

 sed  /year/,/_cons/{//!d}  file

或

 awk  /_cons/{p=0};!p;/year/{p=1}  file

Answer 4

You can do it visually. Just open the file with gVim, and run the command:

:g/^s*year/+1,/^s*_cons/-1 d

Explanation:

g global command
/^s*year/+1 match line bellow year
/^s*_cons/-1 match line above _cons
d delete the range

Answer 5

3. 总结和概括两个全球联盟的解决方案:

sed  /BEGIN/,/END/{/BEGIN/!{/END/!d;}}  input.txt
sed  /BEGIN/,/END/{//!d}  input.txt

Following is the Output with your input-data file:

Test2:

Explanation:

友情链接