利用现场地图,我们可以确定某些途径,在固定配对前线工作,并允许申请分胎。 我要具体指出,所有低于特定道路的要求都采用某种模板。 因此,我谨:
Menu(Loc("show_theme", Link("show" :: "theme" :: Nil, true, "/show/theme"), "Show Theme") )
a. 收集所有要求/show/theme/*(的确如此),但利用模板/show/theme(它没有)服务
我想(例如)/show/theme/1利用该模板/show/theme,以及该模板中的氮,将 出Req。
这是可能的吗? 或者,我做的是错事吗? 此时此刻,Im使用/show_theme? 专题=1,但这是一个微不足道的,很难以形式开展工作。
EDIT:I m试图摆脱利用农业研究小组的寄生虫来编码,并将之作为道路结构的一部分。
Loc代表一个页和一个模板。 如果你想要把多卢拉绘制到洛茨,比你想用重提卢拉重写。 例如:
LiftRules.statefulRewrite.append {
case RewriteRequest(ParsePath("show" :: "theme" :: theme :: Nil, _, _, _), _, _) =>
RewriteResponse(ParsePath("show_theme" :: Nil, "", true, false), Map("theme" -> theme), false)
}
怎么做,与要求/show/theme/* 相匹配,并将之改写到/show_theme? 主题=专题}。 你们创立了你的Loc,以回应URL,你可以把主题变数作为问答参数(S.param(“theme”)。
说明:你可以更简明的方式利用洛茨·瓦卢,但我认为,了解在场面上出现的情况是好事。
如果你们需要更多的帮助,我建议你向以下网站发出信息:Lift/2009/3 Group。 我认为,你会找到比你对SO更迅速的答复。
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