我在某个文件夹中有几个子子,有文件2.sh~。 我想通过手稿删除这一档案,而单凭单在一行书写,而不是在一栏书写。 [Edit: 此处适当格式,以便澄清]
for i in `ls *`; do
if [ -d $i ]; then
cd $i
rm d2.sh~
cd ..
fi
done
这没有给我留下任何错误,但未能从分局删除<代码>d2.sh~。 因此,我想知道我已经犯了什么错误?
我在某个文件夹中有几个子子,有文件2.sh~。 我想通过手稿删除这一档案,而单凭单在一行书写,而不是在一栏书写。 [Edit: 此处适当格式,以便澄清]
for i in `ls *`; do
if [ -d $i ]; then
cd $i
rm d2.sh~
cd ..
fi
done
这没有给我留下任何错误,但未能从分局删除<代码>d2.sh~。 因此,我想知道我已经犯了什么错误?
find /some/path -type f -name "d2.sh~" -delete
你的第一个错误是试图打下ls
。 见,该链接。
Just use for i in *; do ...
.
如果您需要再行,你需要看<>条码>。 或者,如果你有Bash4。 您可以:
shopt -s globstar; for i in **/d2.sh~; do rm "$i"; done
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