我应如何利用双轨搜索来发现,在一阵阵列中,邻居之间的距离是否大于N。 例如:
Input: 2 5 8 11 16
Distance: 4
因此,我们应当回答,邻国之间有这种距离。 (11至16岁)
EDIT: Let me be more clear why I want to do this with binary search.
Assume that the INPUT array comes unsorted. Ex:
Input: 11 8 2 16 5
然后,你们应该打上阵列,看看哪些是邻居。 因此,在我们有一个分类清单之后,找到与双轨搜索的某些突变相距离的最佳途径吗?
在最坏情况下,如果所有数字在<代码>上平摊,你就无法使用双轨搜索。 N 。
采用双轨搜索法和其他分门别类算法的设想是,在每一步骤中,你消除了大约一半的剩余射程。 当所有项目都在<代码>N上登记时,每一系列连续三个或三个以上的项目都可能含有邻近地区的一对“密码”和“N”,因此,你不能消除所审议的两个分方案之一。 您将最终审查每一件连续项目,计算费用:
尽管如此,由于潜在的节奏机会,你或许可以优化一个比<条码>O(NumItems)做得好得多的一般案例。
You (well, I) wouldn t: binary search requires a sorted list, and you ll spend more time sorting this list (of pairs of neighboring items, ordered by their distance) than you would just scanning the list.
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