Question

我有两个相关的模型:Apartment和Lessor。而我需要能够从<代码>Apartment/code>上创建。

In Apartment model:

belongs_to :lessor
before_save :save_lessor
...
def lessor_cellphone= val
  @cellphone = val
end
...
private
def save_lessor
  if Lessor.exists? :cellphone => @cellphone
    self.lessor = Lessor.find_by_cellphone @cellphone
  else
    self.create_lessor :cellphone => @cellphone
  end
  @cellphone = nil
end

。模式:

validates :cellphone, :format => {:with => /d{11}/}, :uniqueness => true
has_many :apartments, :dependent => :nullify

但是,当我试图创建<代码>Apartment而无效cellphone 时,Lessor并不成立,而是建立了“部分”。

验证<条码> 移动电话(而且可能更多)和在<条码>中出现错误的最佳方式是什么?

Answer 1

我认为,最好的解决办法是使用“条形”法,采用“条形”法。

见或。案文。

Nontheless, if you want to use your existing solution: If you return false in a before_* callback all the later callbacks and the associated action are cancelled, see http://api.rubyonrails.org/classes/ActiveRecord/Callbacks.html

So I guess it would be something like

def create_lessor(data)
  # validate data here
  return false if # data not valid
end

def save_lessor
  rc = true
  if Lessor.exists? :cellphone => @cellphone
    self.lessor = Lessor.find_by_cellphone @cellphone
  else
    rc = self.create_lessor(:cellphone => @cellphone)
  end
  @cellphone = nil
  rc  # return the return code
end

这不是一个美丽的解决办法,但我认为,你们有这个想法。

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