Suppose I有一个称为vector的类别,维持一些内部、动态的类型T, 分配于std:alpositionor<T>。 现在,我构造一个<代码>的vector>>,然后想使用移动学,以便我能够使用所消耗的传记<代码>/
vector<unsigned> u(512);
// Do something with v.
vector<double> t = std::move(u);
// Do something with t.
// Later, t gets destroyed.
在<代码>t上使用分配器的存储器,然后使用<代码>t 移动构件,然后用<代码>t 分配器处理? 如果是的话,我必须做些什么来确保这一行动的安全? I m guessing that I should first calls alplaceor.destroy ( for each elements of u s Internal range using us distributionor.
是的,这是STL的宗旨设计之一,一个拨款人所分配的记忆可以由另一个拨款人分配。 这是因为他们想要能够在集装箱之间交换元素(例如<代码>list:splice<>/code>),而不必与其配方做任何事。 这是(原因之一)为什么你能够真正拥有国有拨款。
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