Question

I have a windows batch file, which iterates over files in a folder and runs a command on each file. Specifically I am running xmllint to validate some files:

for %%i in (c:	emp*.xml) do (
   C:XMLLINTxmllint -noout -schema "C:schemasschema.xsd" "%%~dpnxi" >> c:output.txt
)

它目前显示屏幕上的产出。我想显示所有这些指挥部在产出档案中的产出。我如何能够做到这一点? 通过使用配对操作员(>>)来,除创建空白档案外,没有完成任何工作。

这是否是因为食肉?

Answer 1

如果你试图从该方案中转呈错误产出,则可能写上斜体。您可以尝试将其与:

for %%i in (c:	emp*.xml) do (
   C:XMLLINTxmllint -noout -schema "C:schemasschema.xsd" "%%~dpnxi" >> c:output.txt 2>&1
)

Basically the 2>&1 at the end means redirect anything from stderr (which is 2) to stdout (which is 1). Since stdout is redirected to a file, you should now see the stderr stream in the file. Hope this works for you!

Answer 2

I ve never used it, but if its documentation is here, have you tried just removing your "-noout" option, or adding an: "-output c:output.txt"?

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