Question

我感到困惑的是,在贾瓦邦的所作所为之下,我知道,在贾瓦,不可能出现静态继承,那么我如何能够呼吁A的B类固定成员?

public  class A {
  static int staticVariable = 5;
  public static void staticMethod(){
  System.out.println("A");
 }
}
public class B extends A{}
public class C {
    public static void main(String[] args) {
      A.staticMethod();
      B.staticMethod();
      System.out.printf("A s int value %d and B s int value is %d",A.staticVariable,B.staticVariable);
    }
}

产出:

A
A
A s int value 5 and B s int value is 5

Answer 1

你在这里做的不是“法定继承”,而是指简单旧的名称(在汇编时间)。这样做是为了使你能与B一道获得名字,除非B本身界定姓名。

Answer 2

例见static members is<>em>s>。缩略语

Answer 3

For class methods, the runtime system invokes the method defined in the compile-time type of the reference on which the method is called. For instance methods, the runtime system invokes the method defined in the runtime type of the reference on which the method is called.

Read this article for more details: http://krsethur.wordpress.com/2005/12/15/static-method-inheritance/

Answer 4

我认为静态方法/可变性与使用OP语言一样。

友情链接