Question

function isInteger(char) {
    return (char.toString().search(/^-?[0-9]+$/) == 0 )
}
function validateQuan() {
var minExist = "false";
    for (i=0; i<3; i++) {
        var j = document.getElementById("ProductQuantity_"+i).value; 
        if (isInteger(j) && j > 0) {minExist = "true";alert("oi");} 
    }
    if (minExist == "true") {$("#pvs_form").submit();} else {alert("Please enter at least one valid quantity");}
}

Above is my code, it s working on FF 3.6 and IE8, but not with IE7. At IE7 "if (isInteger(j) && j > 0)" couldn t lead to "true". Even i remove "j > 0" and use "[1-9]" on regex.

任何更好的解决办法?

<><>>:> or,reg,任何编号<代码>> 9也属于“真实”。

edit : big sorry to all, i just found that the main problem actually because i got other form at the same page with the same id "ProductQuantity_"+i, and likely it turn the IE7 to only look at the first element with that id found on page. Maybe my original code was working actually, but thx to remind me that the regex is not as expected and to get better code. Thx and sorry once more.

Answer 1

   var isInteger = function( str ) { 
      return  (str|0) == str;
    };

2. 减去点数后再确保点起点起点起伏数或数点被替换为绝缘

isInteger("3.4") // false
isInteger("abc") // false => "abc"|0 = 0
isInteger("3") // true

现在:

function validateQuan() {
    var minExist = false ;
    for (var i = 0; i < 3; i++ ){
        var j = document.getElementById("ProductQuantity_"+i).value; 
        if ( isInteger( j ) && j > 0 ) {
            minExist = true; 
            alert("oi");
            break; // goal achieved, break loop
        } 
    }
    if ( minExist ) {
        $("#pvs_form").submit();
    } else {
        alert("Please enter at least one valid quantity");
    }
}

Answer 2

Try:

function validateQuan() {
    var minExist = "false";
    for( i=0; i<3; i++) {
        var j = parseInt(document.getElementById("ProductQuantity_"+i).value);
        if( !isNaN(j) && j > 0) {minExist = "true"; alert("oi");}
    }
    if( minExist == "true") {...} else {...}
}

Answer 3

Try:

function isInteger(char) {
    return Number(char) == parseInt(char);
}

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