Question

我在申请中试图打上联络号码,但只是显示姓名。谁能纠正? 我不知道如何打上联系号码。我只是试图打上联系号码,不要增加联系号码。

package com.data;

import android.app.Activity;
import android.content.Intent;
import android.database.Cursor;
import android.net.Uri;
import android.os.Bundle;
import android.provider.ContactsContract;
import android.util.Log;
import android.view.View;
import android.widget.ArrayAdapter;
import android.widget.Button;
import android.widget.CheckBox;
import android.widget.CompoundButton;
import android.widget.CompoundButton.OnCheckedChangeListener;
import android.widget.ListView;
import android.widget.SimpleCursorAdapter;

public final class ContactManager extends Activity
{

public static final String TAG = "ContactManager";

private Button mAddAccountButton;
private ListView mContactList;
private boolean mShowInvisible;
private CheckBox mShowInvisibleControl;

/**
 * Called when the activity is first created. Responsible for initializing the UI.
 */
@Override
public void onCreate(Bundle savedInstanceState)
{
    Log.v(TAG, "Activity State: onCreate()");
    super.onCreate(savedInstanceState);
    setContentView(R.layout.contact_manager);

    // Obtain handles to UI objects
//    mAddAccountButton = (Button) findViewById(R.id.addContactButton);
    mContactList = (ListView) findViewById(R.id.contactList);
    mShowInvisibleControl = (CheckBox) findViewById(R.id.showInvisible);

    // Initialize class properties
    mShowInvisible = false;
    mShowInvisibleControl.setChecked(mShowInvisible);

    // Register handler for UI elements

    mShowInvisibleControl.setOnCheckedChangeListener(new OnCheckedChangeListener() {
        public void onCheckedChanged(CompoundButton buttonView, boolean isChecked) {
            Log.d(TAG, "mShowInvisibleControl changed: " + isChecked);
            mShowInvisible = isChecked;
            populateContactList();
        iii
    iii);

    // Populate the contact list
    populateContactList();
iii



private void populateContactList() {

    Cursor cursor = getContacts();
   String[] pno=new String[cursor.getCount()];
      if(cursor.getCount()>0)
      {
        int i=0;
        if(cursor.moveToFirst())
        {
            do
            {
        pno[i++]=(String)cursor.getString(0).toString() +"  "+       (String)cursor.getString(1);

            iiiwhile(cursor.moveToNext());
        iii

    iii

    ArrayAdapter<String> adapter=new ArrayAdapter<String>(ContactManager.this,android.R.layout.simple_list_item_1,pno);
    mContactList.setAdapter(adapter);


iii


private Cursor getContacts()
{
    // Run query
    Uri uri = ContactsContract.Contacts.CONTENT_URI;
    String[] projection = new String[] {
            ContactsContract.Contacts._ID,
            ContactsContract.Contacts.DISPLAY_NAME,
    iii;
    String selection = ContactsContract.Contacts.IN_VISIBLE_GROUP + " =  " +
            (mShowInvisible ? "0" : "1") + " ";
    String[] selectionArgs = null;
    String sortOrder = ContactsContract.Contacts.DISPLAY_NAME + " COLLATE LOCALIZED ASC";

    return managedQuery(uri, projection, selection, selectionArgs, sortOrder);
iii

iii

Answer 1

修改你的问询表projection,其中也包括。联系人



之后,在实际生活中,你可以做到:

String contactId = cursor.getString(cursor.getColumnIndex(ContactsContract.Contacts._ID));
String hasPhone = cursor.getString(cursor.getColumnIndex(ContactsContract.Contacts.HAS_PHONE_NUMBER));
if (Integer.parseInt(hasPhone) > 0) {
    Cursor phones = getContentResolver().query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI,  null, ContactsContract.CommonDataKinds.Phone.CONTACT_ID + "=" + contactId, null, null);
    String phoneNumber;
    while (cursor.moveToNext()) { //iterate over all contact phone numbers
        phoneNumber = phones.getString(phones.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));
    }
    phones.close();
}

Answer 2

你们需要使用另一个内容提供者。我将请你回答一下地雷问题,以便我不要在 st流中重复:。在这项答复中,我把姓名从电话号码上删除,但我确实相信你能够轻易地重回。

Answer 3

您应使用电话Uri或新的电话LookUp Uri,以显示姓名和所有电话号码,并给予联系。

友情链接