Question

I have scrit which makes revision date from current date to 2 or x years later. What I need is to create script based on date which passed 2 days over. Let s say I need to make input record in mysql db for job that were done some days ago an put that date in table and calculate revision date from that date two or x years later. Does someone have an idea how to do that?

我的部分文字:

$formDatum = mysql_real_escape_string($_POST[ formDatum ]);

$date = new DateTime();

switch ($formUsluga) 
{
     case  1 :
         $date -> modify("+2 year");
         $formRev=$date->format("Y-m-d H:i");
         break; 
     case  2 : 
         date_add($date, new DateInterval("P2Y"));
         $formRev=$date->format("Y-m-d H:i:s");
         break;
}

Answer 1

你们是否想增加2年时间?

I believe you could do it like this:

$date = "2012-01-12";
$newdate = strtotime (  +2 year  , strtotime ( $date ) ) ;
$newdate = date (  Y-m-j  , $newdate );

EDIT:

权利我没有看到你已经拥有这一部分。因此,你想要减去过去的日子,然后增加两年?

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