Question

#include<stdio.h>
char *removedps(char *x)
{
    int Ar[256] = {0};
    int ip=0;
    int op=0;
    char temp;
    while(*(x+ip))
    {
       temp  = (*(x+ip));
       if (!Ar[temp])  {
         Ar[temp] = 1;
         *(x+ip) = *(x+op);
         op++;
       }
       ip++;
       *(x+op) =   ;
    }
  return x;
}

int main()
{
  char lo[] = "0001";
  printf("%s",removedps(lo));    
}

My code is not working I have tried hard to see the error All I GET IS the first character . My idea is simple make an array of 256 places insert Zero into them Then insert 1 for each character inside the string (on that position of the array)

Answer 1

your assignment looks to be the error here.

“排位”是指“位置”

因此,

*(x+op) = *(x+ip);

而不是其他方式。

Answer 2

www.un.org/Depts/DGACM/index_french.htm

is always run every iteration of the loop.

我更喜欢这样做(使用你的方法,我很想不亲自使用这种方法)。

char *removedps(char *x)
{
    int Ar[256] = {0};
    char* start = x;
    while(*x)
    {       
        if (Ar[*x])   
        {  // remove the repeated character 
           memmove(x, x+1, strlen(x));
        }   
        else
        {
            Ar[*x] = 1;
            x++;
        }       
    }
    return start;
}

also, I d name it remove_duplicate_chars or something, not a fan of cryptic abbreviations.

Answer 3

页: 1

尝试做的是:

for (op=ip=0;x[ip];ip++) {
 if (!Ar[x[ip]]++) x[op++]=x[ip];
}
x[op]=0;

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