Question

I have 2 dimensional array, I need too calculate mean and standard deviation per row and store it in the proper place. I have write the code but it still give me the wrong result, not giving the correct answer of the intended value. could anyone help me, perhaps my code is just wrong but i dont know how to correct it. Here s the array

enter image description here

And here s the code itself:

public void analyze(String[][] arr) {
   double res = 0.0;
   double avg = 0;
   double variance = 0;
   double SD;
   double Q = 0;
   int index = 0;

   for (int i = 1; i < (arr.length); i++) {
      for (int j = 1; j < (arr[i].length); j++) {
         res = res + Integer.parseInt(arr[i][j]);
      }

      avg = res / (arr[i].length - 1);

      System.out.print("arr[i].length:  " + arr[i].length + "	");
      System.out.println("Average is " + avg);
      /*
      double v = Q + (arr.length - avg) * (arr.length - avg);
      variance = Q / (arr.length - 1);
      SD = Math.sqrt(variance);
      System.out.println("average is " + avg);
      System.out.println("SD");

      double nums[] = { 1.0, 2.3, 3.4, 4.5, 40.5 };
      double result = 0.0;
      for (i = 0; i < nums.length; i++) {
         result = result + nums[i];
      }
      System.out.println("Average is =" + result / nums.length);
      */
   }   
}

Answer 1

页: 1 位于 Java的阿雷拉指数为零。这使你完全错过第一行,下行各翻一栏。

Change

    for(int i=1; i<(arr.length);i++){
        for(int j=1;j<(arr[i].length);j++){
        res = res+Integer.parseInt(arr[i][j]);
    }

to

    for(int i=0; i<(arr.length);i++){
        for(int j=0;j<(arr[i].length);j++){
        res = res+Integer.parseInt(arr[i][j]);
    }

Answer 2

页: 1 Q 。你们需要重新确定您的外 lo的每 it之间的计算变量。

友情链接