Question

我的表格如下:

“entergraph

Consider the table id="testtable", and there is no class or id to uniquely identify the specific td shown in the above screen.

我找到了在下面这样的例子中第二次接触的办法。

“entergraph

但是,一只 go子在第二胎中进入第二胎。

Anyone could you please give me a hand on this?

Thanks

Answer 1

或许可以帮助您:

#testtable tbody > tr:first-child+tr > td:firt-child+td
{
}

或您可使用:nth-child pseudo等类:

#testtable > tr:nth-child(2) > td:nth-child(2)
{

}

<<>strong>,虽然这在年长的浏览器(或IE)中赢得了笔工作,但你需要给囚室一个班级或在该案例中使用java书写器。

Answer 2

您可使用:nth-child()

#testtable tbody >:tr:nth-child(2)
{

}