I have Two Image Views Defined in Xml. I want to Change the Position of One of them Dynamically while the Other remains constant.?? Any Suggestions. Thanx.
当然,这是可能的。 Use LayouParam
ImageView img1=(ImageView) findViewById(R.id.imageview);
ImageView img2=(ImageView) findViewById(R.id.imageview);
RelativeLayout.LayoutParams lp2=new RelativeLayout.LayoutParams(100, 100);
lp2.addRule(RelativeLayout.ALIGN_RIGHT,img2.getId());
img1.setLayoutParams(lp2);
<>Setting Margin
lp2.setMargins(Left, TOp, right,Bottom);
你们可以通过为<编码>提供新的规则来做到这一点。 类似情况:
RelativeLayout.LayoutParams params = imageView2.getLayoutParams();
params.addRule(RelativeLayout.CENTER_IN_PARENT);
imageView2.setLayoutParams(params);
让我们塑造你们的形象 意见1 联系中心由母体组成。 你们的第二次形象 观点2与图像1保持一致,现在,你希望将其与形象以下保持一致。 观点1。 实现以下目标:
RelativeLayout.LayoutParams params = imageView2.getLayoutParams(); param.addRule(RelativeLayout.BELOW, R.id.imageView1); imageView2.setLayoutParams(params);
Use the layout property like this:
imageView.layout(l,t,r,b);
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