Question

我有一系列目标。

([date]=>2012-01-09, [count]=>5),
([date]=>2012-01-11, [count]=>7),
([date]=>2012-01-12, [count]=>5)

将阵列改成阵列或阵列的最佳方式

([date]=>2012-01-08, [count]=>0),
([date]=>2012-01-09, [count]=>5),
([date]=>2012-01-10, [count]=>0),
([date]=>2012-01-11, [count]=>7),
([date]=>2012-01-12, [count]=>5),
([date]=>2012-01-13, [count]=>0),
([date]=>2012-01-14, [count]=>0)

考虑到2012-01-08年启动和2012-01-14结束

Answer 1

generate date from startdate to enddate
create an empty associative array to store your datewise data.
traverse all the dates generated in #1 one by one
if the count for current date exists in initial array, store that in array created in #2, else store count as 0, with array key being (string) $currentDate
the array of step#2 will now have the required data.

将这些内容转化为PHP代码:

Answer 2

我为你们写了这部法典,但我向你们提供算法。

$compArray = new array();

loop from startdate to enddate as date
{
    if (in_array(date, yourarray))
        copy the entry from yourarray to compArray
    else
        enter date into compArray with a count of 0
}

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