i 有一个表格,包括:
mid , email
1 , user_a@...
2 , user_b@...
3 , user_c@...
之后,又加上以下领域/价值观的表
tid, name
1, t_a
2, t_b
3, t_c
其他表格
tid, mid
1, 1
1, 2
1, 3
2, 2
2, 3
3, 1
3, 2
如何让所有有t_a和t_b的用户参与进来。 i 回返的需要
user_a,
user_c
因为用户_b 不含t_a
SELECT e.email
FROM emails e
INNER JOIN email_tags et
ON e.mid = et.mid
INNER JOIN tags t
ON et.tid = t.tid
WHERE t.name IN ( t_a , t_b )
GROUP BY e.email
HAVING COUNT(DISTINCT t.name) = 2
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