在C++中是否有内在病媒功能来扭转病媒的形成?
或者,你只是需要人工做吗?
在C++中是否有内在病媒功能来扭转病媒的形成?
或者,你只是需要人工做吗?
<代码>std:reverse in algorithm
为此的负责人。
#include <vector>
#include <algorithm>
int main() {
std::vector<int> a;
std::reverse(a.begin(), a.end());
return 0;
}
所有集装箱都提供其含量的view>,rbegin(
和rend(>
>。 这两项职能交还了反转器,可像正常功能一样使用,但将像集装箱一样看待。
#include <vector>
#include <iostream>
template<class InIt>
void print_range(InIt first, InIt last, char const* delim = "
"){
--last;
for(; first != last; ++first){
std::cout << *first << delim;
}
std::cout << *first;
}
int main(){
int a[] = { 1, 2, 3, 4, 5 };
std::vector<int> v(a, a+5);
print_range(v.begin(), v.end(), "->");
std::cout << "
=============
";
print_range(v.rbegin(), v.rend(), "<-");
}
1->2->3->4->5
=============
5<-4<-3<-2<-1
页: 1 ......
std::reverse(str.begin(), str.end());
通常,你想要扭转病媒的原因是,你通过把所有项目推向尾来加以填充,但实际上却以相反的方式接收这些物品。 在这种情况下,你可以通过使用<条码>dque<>/条码”来扭转集装箱状况,直接将其推向前线。 (您可在前面加上<代码>查询器:insert(<>>>/code>,但是,如果存在大量物品,则会很慢,因为它必须把所有其他物品放在每一处插入。) 而不是:
std::vector<int> foo;
int nextItem;
while (getNext(nextItem)) {
foo.push_back(nextItem);
}
std::reverse(foo.begin(), foo.end());
否则:
std::deque<int> foo;
int nextItem;
while (getNext(nextItem)) {
foo.push_front(nextItem);
}
// No reverse needed - already in correct order
也可使用<代码>std:list ,而不是std:vector <>code>
list/code>, 具有内在功能list:reverse, 用于逆转内容。
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