我的田地价值为xxx-xxx-xxxxx-xxxx-x。 如何从该法典中摘取第10条的性质。
I noticed that there were some threads with similar questions, and I did look through them but did not really get a convincing answer. Here s my question: The subquery below returns a Table with 3 ...
我的田地价值为xxx-xxx-xxxxx-xxxx-x。 如何从该法典中摘取第10条的性质。
select substring( xxx-xxx-xxx-xxxxx-xx-x , 10, 1)
关于MSDN的功能的文件是here。
Fiddle demo是。 (用不同信件,你可以清楚地看到哪封信摘取。)
使用<条码> 职能
选定次体 (xxx-xxx-xxxxxx-xx-x , 10, 1)
您可使用http://technet.microsoft.com/en-us/library/ms187748.aspx”rel=“noreferer”SUBSTRING
。
SELECT SUBSTRING(field, 10, 1)
<>field/strong> 是回报数值的。
declare @x varchar(20) = xxx-xxx-xxx-xxxxx-xx-x
select SUBSTRING(@x,10,CHARINDEX( - ,@x)-4 )
下面的法典将在划界之后从左边或右边再重新编号;具体来说,划界员是 com,它正在寻找第2部分,从右边计算。
declare
@str_orig VARCHAR(256)= 123,345,8,6,7 ,
@delimit varchar(50) = , ,
@loc int =2,
@from_left bit =0
SELECT value, row_number() over( order by( select 1)) as row_num
into #split
FROM STRING_SPLIT(@str_orig, @delimit)
declare @result varchar(256)
if @from_left=1
begin
set @result = ( select top 1 value from #split where row_num=@loc)
end
else
begin
set @result = ( select top 1 value from #split
where row_num= (SELECT MAX(ROw_num) -(@loc-1) FROM #split)
)
end
select @result
I noticed that there were some threads with similar questions, and I did look through them but did not really get a convincing answer. Here s my question: The subquery below returns a Table with 3 ...
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