Question

我有这项服务。

itemList= signal<Item[]>([]);
reset(){
   this.itemList.set([]);
}
add(item){
 this.itemList.update(list => {
  const ind = list.findIndex(o => o._id == item._id);
  if (ind !== -1) {
    list.splice(ind, 1);
  } else {
    list.push({_id:item._id,name:item.name});
  }
  list.sort((a, b) => a.name > b.name ? 1 : a.name === b.name ? 0 : -1);
  return list;
})
}
itemCount = computed(() => this.itemList().length);

重整职能和增加项目按预期进行,但项目Count没有更新,总是是欧洲区域办事处。

我通过直接在以下网址获得服务:service.itemCount(<>/code>,并做t工作。什么是错的?


但是,如果我使用<条码>服务.itemList(>)。
<>>>>>
问题请见<017href=”https://stackblitz.com/edit/stackblitz-starters-hvntvw?description=An%20angular-cli%20project%20on%20@angular/animations,%20@angular/common,%20@angular/compiler,%20@angular/core=angular/forms,%20@angular/platform-browser-dynamic,%20angular@angular/router%20jal%20js%20amp。

Answer 1

如果你不改变这一提法,那么,分子将假定价值不变,并赢得更新。

仅改变贵重回报价值,以换取新的价值

return [...list];

Answer 2

Caio is correct: there was a last-minute change to the signals API that made in-place mutations no longer work. For a more detailed answer, you can see my response here.

友情链接