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Accessing an Enumeration association value in Swift (10 answers)

Closed 2 years ago.

我用参数写了这个大体。

public enum ButtonType {
    case number(value: String)
    case clear(value: String)
    case backspace(value: String)
    
    static func generateNumpad() -> [ButtonType] {
        return [
            .number(value: "1"),
            .number(value: "2"),
            .number(value: "3"),
            .number(value: "4"),
            .number(value: "5"),
            .number(value: "6"),
            .number(value: "7"),
            .number(value: "8"),
            .number(value: "9"),
            .clear(value: "Clear"),
            .number(value: "0"),
            .backspace(value: "Del"),
        ]
    }
}

鉴于控制器,我把所有纽子类划入一个阵列。

let buttons = ButtonType.generateNumpad()

How can I get the parameter value? example: buttons[0].value

请帮助!

Answer 1

在<条码>中类型,申报财产如下:

enum ButtonType {
    ...
    var value: String {
        switch self {
        case .number(let number): return number
        case .clear(let clearValue): return clearValue
        case .backspace(let backSpaceValue): return backSpaceValue
        }
    }
}

友情链接