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Safely turning a JSON string into an object (28 answers)

Closed 8 mins ago.

我正试图通过一种PHP的呈文形式将阵列结果退回到 j。我可以通过<>Toast发出一个成功或失败的信息。

我正在使用:

$ret["icon"] = "success";
$ret["title"] = "Request Deleted Successfully";
echo json_encode($ret);

结果是:

{"icon":"success","title":"Request Deleted Successfully"}

但是,为了激发 object子,我需要

Toast.fire({icon:  success ,title:  Request Deleted Successfully. })

看看差异,我只需要从阵列钥匙中删除 com子,但我如何能够在 j或 Java本中这样做?

Answer 1

You receive a JSON string and need to convert it to an object.

const string =  {"icon":"success","title":"Request Deleted Successfully"} ;
const object = JSON.parse(string);
console.log(object.title);

• 派遣PHP正确负责人(在任何其他产出之前)

header("Content-Type: application/json");

您应直接从酒吧收到物品,无需打上。

Answer 2

辛勤工作

function(data, status) {
  if (status === "success") {
    if (pageLink == "approverequest") {
      Toast.fire(JSON.parse(data));
      loadDataTableButtons("#requests-container","#project-requests"," .DIR. admin/dashboard/requests");
    } else {
      Toast.fire(JSON.parse(data));
      loadDataTableButtons("#requests-container","#project-requests"," .DIR. admin/dashboard/requests");
    }
  }
});

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