Question

I m 尝试采用execve()的新工艺,从os模块中选取。我需要启动新的进程,在另一个司中做一些 st子,但我还是取得了一些变化。

code:

import os

os.execve( /bin/ls , [ /bin/ls ], { PATH :  /tmp })

i 操作该代码时,即从<代码>/tmp的目录上看一米。什么是错的? 我不能使用<代码>os.chdir()或改变指挥方式(如使用模块subprocess)

Answer 1

Change your current working directory before calling execve(). The CWD will be inherited by the new process.

import os
os.chdir( /tmp )
os.execve( /bin/ls , [ arg1 ,  arg2 ], { PATH :  is_inherited_anyway })

Answer 2

如果有<代码>/bin/sh,可:

import os
target_dir =  /tmp 
your_target_command_with_args =  ls  # Just put the arguments for the command space-separated in this string, as if this string were your system s default shell.
os.execve( /bin/sh , [ /bin/sh ,  -c , f cd "{target_dir}"; {your_target_command_with_args} ], {})

如果具体涉及<代码>/bin/ls,你实际上可以提出这一论点(其他一些方案也支持作为论据的道路),例如:

import os
target_dir =  /tmp 
os.execve( /bin/ls , [ /bin/ls , target_dir], {})

I think your approach didn t work because ls just doesn t read the PATH envvar to determine what directory to list, which you set in the third argument (when I omitted that, os.execve complained about the argument env (position 3) missing).

Also, the PATH envvar normally contains a colon-separated list of directories in which a command is searched for, like /usr/local/sbin:/usr/local/bin:/usr/sbin:/usr/bin:/sbin:/bin:/usr/games:/usr/local/games:/snap/bin. If you enter the command ls in any shell it searches in each of these directories for a file called ls and the first one it finds is then run.

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