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结构更新一栏,具有目前和以往各行之差价值
原标题:SQL updating column with a difference value of current and previous row
  • 时间:2023-12-13 17:18:50
  •  标签:
  • sql
  • t-sql

我的表格载有累计降雨量数据。 我想计算每张记录的降雨量,并以这一价值更新表格。

下表是:

ID date WsRaincount Rain
1 2023-07-01 13:01 10
2 2023-07-01 13:05 10.2
3 2023-07-01 13:10 10.3

结果是:

ID date WsRaincount Rain
1 2023-07-01 13:01 10 0
2 2023-07-01 13:05 10.2 .2
3 2023-07-01 13:10 10.3 .1

可使用<代码>LAG()功能计算差额:

SELECT  
    ([wsraincount]) - (LAG([wsraincount]) OVER (ORDER BY [id])) AS RainDiff

我的问题是,我现在如何看待<条码>RainDiff的价值,并将其放在适当的雨栏中?

问题回答

您可以使用一个表率表或计算表(并直接更新,无需重新加入)。

UPDATE WithDiff
SET Rain = RainDiff
FROM (
    SELECT *,
      wsraincount - LAG(wsraincount) OVER (ORDER BY id) AS RainDiff
    FROM yourTable t
) WithDiff;




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