我有以下法典,试图将功能 f与变数挂钩,但需要接受参数(必须事先计算)。 我如何通过(t)功能在 c子中转过?
f = @(t)(cfb.*t)
...
cfb = %Something
<编码>d = 整体(f、0、上限>
我如何改变这一法典,以便f 能够把 t(从整体上)和 c作为参数? 我只尝试修改其编号为f=@(t,cfb)
integral(f(cf)(b)>,但这只是造成一种错误,即没有计算足够参数。
我有以下法典,试图将功能 f与变数挂钩,但需要接受参数(必须事先计算)。 我如何通过(t)功能在 c子中转过?
f = @(t)(cfb.*t)
...
cfb = %Something
<编码>d = 整体(f、0、上限>
我如何改变这一法典,以便f 能够把 t(从整体上)和 c作为参数? 我只尝试修改其编号为f=@(t,cfb)
integral(f(cf)(b)>,但这只是造成一种错误,即没有计算足够参数。
你利用匿名职能的想法是好的。 Just definition cfb
before that
cfb = %Something
f = @(t) (cfb.*t)
d = integral(f, 0, upperLimit)
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