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Matlab与不断变数相结合。
原标题:Matlab Integral with passing in a constant variable.
  • 时间:2013-02-03 17:54:01
  •  标签:
  • matlab

我有以下法典,试图将功能 f与变数挂钩,但需要接受参数(必须事先计算)。 我如何通过(t)功能在 c子中转过?

f = @(t)(cfb.*t)

... cfb = %Something

<编码>d = 整体(f、0、上限>

我如何改变这一法典,以便f 能够把 t(从整体上)和 c作为参数? 我只尝试修改其编号为f=@(t,cfb)integral(f(cf)(b)>,但这只是造成一种错误,即没有计算足够参数。

最佳回答

你利用匿名职能的想法是好的。 Just definition cfb before that

cfb = %Something
f = @(t) (cfb.*t)
d = integral(f, 0, upperLimit)
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