Question

我知道,授权法可以通过授权重新定向获得,而且已经这样做。

我在上建立了图表目录编号,并且它确实做了工作,但只是针对第一份APIC申请,因此发现的任何替代要求都不存在出入错误。

final String clientId = "YOUR_CLIENT_ID";
final String tenantId = "YOUR_TENANT_ID"; // or "common" for multi-tenant apps
final String clientSecret = "YOUR_CLIENT_SECRET";
final String authorizationCode = "AUTH_CODE_FROM_REDIRECT";
final String redirectUrl = "YOUR_REDIRECT_URI";
final List<String> scopes = Arrays.asList("User.Read");

final AuthorizationCodeCredential credential = new AuthorizationCodeCredentialBuilder()
    .clientId(clientId).tenantId(tenantId).clientSecret(clientSecret)
    .authorizationCode(authorizationCode).redirectUrl(redirectUrl).build();

if (null == scopes || null == credential) {
    throw new Exception("Unexpected error");
}
final TokenCredentialAuthProvider authProvider = new TokenCredentialAuthProvider(
    scopes, credential);

final GraphServiceClient<Request> graphClient = GraphServiceClient.builder()
    .authenticationProvider(authProvider).buildClient();

它认为,在使用授权办法时,不能把接触打脚。

目前,我试图使整个网络都能获得这一机会,尽管这不是设计的授权守则的正确设想,但我不得不因为现在无法提供客户的缓冲流动。

我要问的是,如何通过图克塞韦茨克利特提供经证实的亚普森要求,以及如何自动获得新机会,以重新标注?

Answer 1

您可使用<代码>AuthorizationCredential认证和授权用户,但只能提供单一途径。旨在处理象征性的ach和象征性的复读。为通过<代码>GraphserviceClient向随后的APIC申请提供凭据,您可创建的事例。制图学学士学位/代码,并通过其认证提供人<编码>。。举例说:


final String clientId = "YOUR_CLIENT_ID";
final String tenantId = "YOUR_TENANT_ID"; 
// or "common" for multi-tenant apps 
final String clientSecret ="YOUR_CLIENT_SECRET"; 
final String authorizationCode = "AUTH_CODE_FROM_REDIRECT";
final String redirectUrl = "YOUR_REDIRECT_URI";
final List scopes = Arrays.asList("User.Read"); 
final AuthorizationCodeCredential credential = new AuthorizationCodeCredentialBuilder().clientId(clientId).tenantId(tenantId).clientSecret(clientSecret).authorizationCode(authorizationCode).redirectUrl(redirectUrl).build();
if (null == scopes || null == credential)
{ throw new Exception("Unexpected error"); }
final TokenCredentialAuthProvider authProvider= new TokenCredentialAuthProvider(scopes,credential);
// Create an instance of GraphServiceClient and pass in the TokenCredentialAuthProvider
final GraphServiceClient graphClient = GraphServiceClient.builder() .authenticationProvider(authProvider).buildClient(); 
// Use the GraphServiceClient to make API requests
final User user = graphClient.me().buildRequest().get()

here和here>here<<<<<<>>

Answer 2

最后,我发现,Azure-identitysdk的认证资格等级中存在一种ug缩,它正确检索了被证明为保密客户提供的卡片。 https://github.com/Azure/azure-sdk-for-java/issues/36994"rel=“nofollow noreferer” 现在已经确定。

友情链接