Question

我如何通过单一<条码>实现这一点? 换言之,if(fruit !”“apple > fruit fruit!”=“range”=不是产生预期的结果?

fruits.forEach(function(fruit){
  if(fruit != "apple"){ // < ----I want to use a compound OR, or compare multiple strings.
    if(fruit != "orange"){ // <---------I want this nested if gone.
      console.log(fruit + " is not apple or orange [two]");
    }
  }
});

const fruits = ["apple","orange","banana","cherry"];

fruits.forEach(function(fruit){
  if(fruit != "apple"){
    console.log(fruit + " is not apple");
  }
});

fruits.forEach(function(fruit){ //<------- this is what I m having problems with
  if(fruit != "apple" || fruit != "orange"){
    console.log(fruit + " is not apple or orange [one]");
  }
});

fruits.forEach(function(fruit){
  if(fruit != "apple"){
    if(fruit != "orange"){
      console.log(fruit + " is not apple or orange [two]");
    }
  }
});

Answer 1

@ Pointy points out:

const fruits = ["apple","orange","banana","cherry"];

fruits.forEach(function(fruit){
  if(fruit != "apple"){
    console.log(fruit + " is not apple");
  }
});

fruits.forEach(function(fruit){ //<------- this is what I m having problems with
  if(fruit != "apple" && fruit != "orange"){ // notice
    console.log(fruit + " is not apple or orange [one]");
  }
});

fruits.forEach(function(fruit){
  if(fruit != "apple"){
    if(fruit != "orange"){
      console.log(fruit + " is not apple or orange [two]");
    }
  }
});

Answer 2

一个线人?

const fruits = [ apple ,  orange ,  banana ,  cherry ];
fruits
  .filter(f => f !==  apple  && f !==  orange )
  .forEach(f => console.log(`${f} is nor apple nor orange`));

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