Question

我是新来的,希望了解情况,因此,我制作了一幅长篇的文字,从分处理到执行双面文字。书目为框架设计了环境,并实施了一套可操作的++方案。

打算使用的是,将假装作为监督C++进程的一种服务,如果C++工艺的出走,则将双管开动。

如果我从指挥线(<>条码/proc_watchdog.py)开始使用纸面文字,那么“滚动”就会继续运行。

如果我随后使用系统格式(系统开字典>)执行字典。服务,C++方案退出。



履历:

[Unit]
Description=RustDedicated watchdog service
StartLimitIntervalSec=0

[Service]
Type=simple
Restart=always
RestartSec=1
User=scriptuser
ExecStart=/path/to/C++_Prog_Dir/proc_watchdog.py

[Install]
WantedBy=multi-user.target


The python script:

#!/usr/bin/python3

import subprocess as sp
import os
import psutil
import time

backgroundProc = "Procname"

def processWatchdog():
   waitCount = 0;

   while True:
      procList = []

      for proc in psutil.process_iter():
         procList.append(proc.as_dict(attrs=[ name ]))

      found = 0
      for pname in procList:
         if backgroundProc == pname[ name ]:
            print("Process running")
            found = 1

      if found == 0:
         print("Process not found...")
         waitCount += 1
         if waitCount == 3:
            p = sp.Popen(["/path/to/C++_Prog_Dir/start.sh"])
            print("Restarting")
            p.wait()
            waitCount = 0
            print("Restarted")

      time.sleep(2)

if __name__ ==  __main__ :
   processWatchdog()


Bash 写法:

#!/bin/bash

./c++_process &>> /dev/null &

exit 0


谁能帮助我理解,为什么要用哪一种方式来对待假装?

Answer 1

父母是否适当等待孩子。当儿童离开时,重新开始。这就是DJB的贱民。

改写:

./c++_process &>> /dev/null &

:

exec ./c++_process &>> /dev/null

Then your watch dog will be alerted immediately when p.wait() returns that it has to restart the program as it had exited. With that your watch dog can be reduced :

import subprocess as sp
import time

def processWatchdog():

   while True:
       p = sp.Popen(["/path/to/C++_Prog_Dir/start.sh"])
       p.wait()

       time.sleep(2)

if __name__ ==  __main__ :
   processWatchdog()

只是重新启动该方案,第二次推迟。

Answer 2

服务参数“KillMode”违约值是“中间集团”,这意味着该单位控制组的所有剩余过程都将被杀死。

“加工”或“无”一使用并运转良好

友情链接