Question

我获得了APICA的回报,并得以与所需的第一部分保持一致。然而,它不是独裁者,而是扼杀。我怎么能够把这种扼杀变成一个字典,以便我能够接触我想要的关键吗?

roster = """*Person 1: Bob
Person 2: Alice
Person 3: Eve
Person 4: Mallory
Person 5: Trent*
"""

迄今为止,我尝试了一种无uck的变式方法,即json 载荷和一些清单缩略语和分法。任何帮助都是巨大的。

我希望把我的名册变量作为字典,这样它就象这样:

roster_dict = { *Person 1*  :  *Bob* ,  *Person 2*  :  *Alice* ,  *Person 3*  :  *Eve* ,  *Person 4*  :  *Mallory* ,  *Person 5*  :  *Trent* }

这是我发现的另一个问题,但在我修改后,我没有工作。

str = " *Jan = January; Feb = February; Mar = March*"

dictionary = dict(subString.split("=") for subString in str.split(";"))

Answer 1

如果你想在一行(尽管你可能 t)中这样做的话,你可以这样做。

roster_dict = dict([["*"+item.strip()+"*" for item in person.split(":")] for person in roster.replace("*", "").splitlines()])

为了看看这些伤口,我们可以逐条加以建构:

>>> roster
 *Person 1: Bob
Person 2: Alice
Person 3: Eve
Person 4: Mallory
Person 5: Trent*
 
>>> roster.replace("*", "")
 Person 1: Bob
Person 2: Alice
Person 3: Eve
Person 4: Mallory
Person 5: Trent
 
>>> roster.replace("*", "").splitlines()
[ Person 1: Bob ,  Person 2: Alice ,  Person 3: Eve ,  Person 4: Mallory ,  Person 5: Trent ]
>>> [person.split(":") for person in roster.replace("*", "").splitlines()]
[[ Person 1 ,   Bob ], [ Person 2 ,   Alice ], [ Person 3 ,   Eve ], [ Person 4 ,   Mallory ], [ Person 5 ,   Trent ]]
>>> dict([["*"+item.strip()+"*" for item in person.split(":")] for person in roster.replace("*", "").splitlines()])
{ *Person 1* :  *Bob* ,  *Person 2* :  *Alice* ,  *Person 3* :  *Eve* ,  *Person 4* :  *Mallory* ,  *Person 5* :  *Trent* }

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