Question

我有两个阵列:

Array1:

ID: 1
ID: 2
ID: 3
ID: 4
ID: 5

Array2, with num Value:

ID: 2, NUM: 200
ID: 4, NUM: 400

我希望产出如下:(如果阵列没有记录,就再增加零)。

ID: 1, NUM: 0
ID: 2, NUM: 200
ID: 3, NUM: 0
ID: 4, NUM: 400
ID: 5, NUM: 0

I am new to PHP, tried array_diff and array_intersect but not find the clue, could you please let me know how can I do that?

感谢。

Answer 1

You can loop through your array1 and add the value of array2 for the current key or 0 if the key is not set in array2.

foreach ($array1 as $key => $value) {
  if (array_key_exists($key, $array2) {
    $array1[$key] = $array2[$key];
  } else {
    $array1[$key] = 0;
  }
}

Answer 2

为了避免对第二阵列进行低效的搜索,有人为便于即时获得价值而进行相关的勘测/勘测。如果在调查中找不到身份证,则对新要素的违约程度为0。

守则:(民主党)

$array1 = [
    [ ID  => 1],
    [ ID  => 2],
    [ ID  => 3],
    [ ID  => 4],
    [ ID  => 5],
];
$array2 = [
    [ ID  => 2,  NUM  => 200],
    [ ID  => 4,  NUM  => 400],
];

$lookup = array_column($array2, null,  ID );
var_export(
    array_map(
        fn($row) => $row + ($lookup[$row[ ID ]] ?? [ NUM  => 0]),
        $array1
    )
);

友情链接