Question

i m 寻求解决两个病媒的有限组成部分,我试图解释。

我知道:数字载体和数字的G(z)矢量。

融合的极限为zmin和zmax。

I should to calculate: Integral between zmin,zmax of [G(z) * z^(7/6)] dz

我能否用以下法典解决?

For i = zmin:zmax
myresult = G(z(i))*z(i)^(7/6)
end

Answer 1

(前)

您可使用

Define G(z) as a function handle, and the function to be integrated as another one. You can find an example in my other answer.

因此,你的目标是计算<代码>[G(z) * z^(7/6)] * dz,其中G(z)和z为预估数字矢量,dz为小增量值。

dz = (zmax - zmin) / length(G(z));
S = G * z  * dz;

<代码>S应为结果。让我解释一下。

First of all, I messed up with G(z) previously (apologize for that). You have already evaluated (partially) the function to integrate, namely G(z) and z.
G(z) and z are number arrays. Arrays are indexed by integer, starting from 1. So G(z(i)) may not be a valid expression, as z(i) haven t been guaranteed to be integers. The code above only works correctly if you have defined G(z) in this way - G(i) = some_function (z(i));. By so each element of the same index in two arrays have a meaningful relation.
There are several ways to evaluate the product of two arrays (vectors), generating a single-value sum. A for loop works, but is inefficient. G * z is the way to calc vector dot product.