Question

我有一个trick问...... 我正在使用山角地图静电灯,以树立一个带有标识的地图的形象。我正在努力做的是,鉴于我想要展示的两个标识的位置,计算适当的动物群。

我有纬度A、长度A、纬度B、长度B和中心点(麻风)。是否有任何人知道解决动物群的公式?

感谢!

Answer 1

I took 3 static maps at levels 11, 12 and 13, and used the "Maps Labs" feature of Google Maps, holding down the shift key at the corresponding min/max latitude/longtitude marks. Then I wrote a Perl program to calculate the latitude/longtitude ranges, the expected values (with the formula I predicted by inspecting the data), and the deltas (ie. abs(expected - range)), which should be close to zero. Once I had convinced myself that I had gotten as close as I could, here were my results:

Z11:  LatRange[0.323999]  ExpLat[ 0.324]  DeltaLat[  0.0000000000000019]
Z11:  LonRange[0.439999]  ExpLon[  0.44]  DeltaLon[  0.0000000000000023]

Z12:  LatRange[0.161999]  ExpLat[ 0.162]  DeltaLat[  0.0000000000000010]
Z12:  LonRange[0.219999]  ExpLon[  0.22]  DeltaLon[  0.0000000000000011]

Z13:  LatRange[0.081000]  ExpLat[ 0.081]  DeltaLat[  0.0000000000000031]
Z13:  LonRange[0.109999]  ExpLon[  0.11]  DeltaLon[  0.0000000000000006]

我所用的公式是:

ExpLat = 0.162 * (2 ** (12 - Z))
ExpLon = 0.220 * (2 ** (12 - Z))

如果ExpLat,ExpLon是预期的纬度和长度范围,Z是动物体。

Answer 2

尽管你正在使用静态地图复印件,但你仍然能够参考常规地图档案,然后进行捆绑盒式计算:

map = new GMap2(document.getElementById("map"));

// Define the two corners of the bounding box
var sw = new GLatLng(59.0, 13.12); //any lat,lng pair
var ne = new GLatLng(60.35, 16.90);

var bounds = new GLatLngBounds(sw, ne);

var zoom = map.getBoundsZoomLevel(bounds));

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