Question

int main()
{ 
char* NamePointer = new char;


std::cout << "Enter the file you want to edit (MUST BE IN THE PROJECT S DIRECTORY): ";
std::cin >> &NamePointer;

const char* FileName = NamePointer;
delete &NamePointer;


return 0;
}

这给我留下了标题中的错误:

std::cin >> &NamePointer;

任何想法? 这可能是一个简单的Im失踪,但当我看一看时,我没有回答。

~~JUST 缩略语我在“&NamePointer”中引用了“和”;~~

Yeah I just found out another way of doing this using c_str(). Sorry!

Answer 1

应:

std::cin >> NamePointer;

此外,你只是给人一种记忆,或许意味着:

char* NamePointer = new char[MAX_SIZE];

并将其定位为:

delete []NamePointer;

请注意,C++这样做的办法是简单使用std:string 处理你利用<代码>char*获取的缓冲外溢问题:

std::string Name;
std::cin >> Name;

Answer 2

There s no need for the address of operator here. Simply:

std::cin >> NamePointer;

我注意到的其他一些事项:

char* NamePointer = new char;

你们可能希望的不仅仅是一个特点。简单开端可能是一大笔固定拨款:

char NamePointer[1024];

在此情况下,请在结尾处删除<代码>delete的说明(亦不使用address of营运人]。

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