Question

我读到,Mongoose将只开一个最长的链接,没有办法改变这一联系。

这是否意味着缓慢的中点会使得随后的所有询问都等待?

我知道一切。 j 不是锁定的,但我很想知道,缓慢的询问是否会拖延执行所有随后的询问。是否有办法改变这种状况。

Answer 1

只有当你使用缺省方法时,才会使用一条连接。为了解决这一问题,你可以建立多种联系,然后将同一图示的模型与这一联系联系起来。

与此类似:

var conn = mongoose.createConnection( mongodb://localhost/test );
var conn2 = mongoose.createConnection( mongodb://localhost/test );
var model1 = conn.model( Model , Schema);
var model2 = conn2.model( Model , Schema);
model1.find({long query}, function() {
   console.log("this will print out last");
});
model2.find({short query}, function() {
   console.log("this will print out first");
});

希望会有所帮助。

Update Hey, that does work. Updating from the comments, you can create a connection pool using createConnection. It lets you do multiple queries from the same model concurrently:

var conn = mongoose.createConnection( mongodb://localhost/test , {server:{poolSize:2}});
var model = conn.model( Model , Schema);
model.find({long query}, function() {
   console.log("this will print out last");
});
model.find({short query}, function() {
   console.log("this will print out first");
});

Update 2 -- Dec 2012
This answer may be slightly outdated now--I noticed I ve been continuing to get upvotes, so I thought I would update it. The mongodb-native driver that mongoose wraps now has a default connection pool size of 5, so you probably don t need to explicitly specify it in mongoose.

友情链接