Question

是否有办法发出<代码>的电话。允许SetForegroundWindow(ASFW_ANY)?

大图片:

I want a single process of my exe running at a time.
To achieve it, the processes communicates with each other using named pipes & if a process already exists, its window has to be brought into front.
To be able to do this, the latest process must set AllowSetForegroundWindow() with the existing process id.
- I do not want to fetch the process id (sorry for my laziness), so what I m planning to do is: 1. call AllowSetForegroundWindow() with ASFW_ANY 2. Just in case some error occurred, undo the call to AllowSetForegroundWindow() so that others cannot steal focus from my process.

简言之,我想允许其他进程从我那里偷走重点,在某个时间窗口中,只有......。

任何人都曾遇到过类似的问题,发现有任何工作关系?

另外,请让我知道,你是否有任何更好的建议。

Answer 1

根据号文件,目标过程(通常包括“任何”)将失去在你打电话<代码>后从你那里偷走重点的能力。允许SetForegroundWindow。

In other words, it sounds like you can have only one such permission active at a time.

因此,你应该能够取消许可,要求获得一些不存在的身份证,或或许是你自己的程序。然而,这是理论。

我个人只是把目标过程ID放在指定管道上。

Answer 2

如果我理解你的主要要求,只有一次提出申请。如果你所描述的一切只是符合这一要求的,而不是一些更伟大的计划的一部分,那么实现这一要求的途径就更加简单。

You can create a global named mutex when your application starts. All other instances will see this mutex as set, and simply quit immediately. Here s the quick and dirty of it:

// Multiple instances detection
HANDLE my_mutex = ::CreateMutex(NULL, FALSE, "Global\MyCuteFluffyMutex" );

int create_mutex_error = ::GetLastError();
bool already_running =
          ( my_mutex && ( create_mutex_error == ERROR_ALREADY_EXISTS ))
       || ( create_mutex_error == ERROR_ACCESS_DENIED );

if ( !already_running ) {
  // Run my application
}

::CloseHandle(my_mutex);

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