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X++ Com Out Of QueryRun in Fetchmeth
原标题:X++ Coming Out Of QueryRun In Fetch Method

为此,我似乎无法找到解决办法。 我在一份报告中修改了Fetch方法,这样,如果问题Run发生变化,新的国际发展法则有缺陷,那么,随着休息时间的推移,新一页出现,2个部分被执行。 这一部分进行罚款,下半部分在每份身份证上没有几本记录,我正在使用Element。 处理。 情况是,选择了第一个识别资料,完成了报告的内容(本人)并按预期发送了该内容,然而,在排位不上下一个识别资料时,情况如何?

这里是法典;

public boolean fetch()
{
    APMPriorityId           oldVanId, newVanId;
    LogisticsControlTable   lLogisticsControlTable;
    int64                   cnt, counter;
    ;

    queryRun = new QueryRun(this);

    if (!queryRun.prompt() || !element.prompt())
    {
        return false;
    }

    while (queryRun.next())
    {
        if (queryRun.changed(tableNum(LogisticsControlTable)))
        {
            lLogisticsControlTable = queryRun.get(tableNum(LogisticsControlTable));
            if (lLogisticsControlTable)
            {
                info(lLogisticsControlTable.APMPriorityId);
                cnt      = 0;
                oldVanId =  newVanId;
                newVanId =  lLogisticsControlTable.APMPriorityId;

                if(newVanId)
                {
                    element.newPage();
                    element.execute(1);
                    element.execute(2);
                }
            }

            if (lLogisticsControlTable.APMPriorityId)

            select count(recId) from lLogisticsControlTable where lLogisticsControlTable.APMPriorityId == newVanId;
            counter = lLogisticsControlTable.RecId;

            while select lLogisticsControlTable where lLogisticsControlTable.APMPriorityId == newVanId
            {
                cnt++;

                if(lLogisticsControlTable.APMPriorityId == newVanId && cnt <= counter)
                {
                    element.execute(3);
                    element.send(lLogisticsControlTable);
                }
            }
        }
    }
    return true;
}
最佳回答

页: 1 然而,这两种用途都受到干扰;有两家“Q”控制器。

使用两种不同的记录变量。

问题回答

暂无回答




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