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多部分json的使用参数
原标题:accessing parameters of multipart json

我曾要求设立一个铁路客运机服务器,该服务器认为:

POST /api/posts.json HTTP/1.1
Accepts: application/json
X-API-KEY: 7d867d16a5e25337b6d7857965f812bee73b76ac
Content-Length: 288
Content-Type: multipart/form-data; boundary=syoYQUQsGwI2XqShQimFdv2QSe-_GYbjVx40T1kS
Host: 10.0.2.2:3000
Connection: Keep-Alive
User-Agent: Apache-HttpClient/UNAVAILABLE (java 1.4)

--syoYQUQsGwI2XqShQimFdv2QSe-_GYbjVx40T1kS
Content-Disposition: form-data; name="DATA"
Content-Type: application/json; charset=UTF-8
Content-Transfer-Encoding: 8bit

{"tags":["dffdff"],"location_id":3,"post":{"content":"test #dffdff"}}
--syoYQUQsGwI2XqShQimFdv2QSe-_GYbjVx40T1kS--

我如何接触JSON params?

如果我写了字句,以显示我的属性,但所nes的一切都是空洞的(例如,寄生虫[:DATA][后post]或寄生虫[:DATA][:标签]

最新资料:

当我试图做事时

Rails.logger.debug(params[:DATA]) 

{"tags":["dffdff"],"location_id":3,"post":{"content":"test #dffdff"}} 

但我却在尝试

Rails.logger.debug(params[:DATA][:post]) 

TypeError (can t convert Symbol into Integer):
  app/controllers/api/posts_controller.rb:19:in `[] 
  app/controllers/api/posts_controller.rb:19:in `create 
最佳回答

您的问题是,<条码>[:DATA]是一种扼杀,但你正在把它当作一种 has处理。

你们需要把JSON-string编成一个Ruby,就像:

     data = JSON.parse(params[:DATA])
     puts data[ post ]

如果你想要在散列中使用符号,即<代码>[:post],那么你可以做到:

     data = data.with_indifferent_access
     puts data[:post]

NB. 如果你想用一种 rub光加以检测,而不是使用<条码>[:DATA],则你可以将第一种数据输入:

     data = JSON.parse( {"tags":["dffdff"],"location_id":3,"post":{"content":"test #dffdff"}}  )
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