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我用我的手脚与Sandajax一道,想为这一询问印刷一个插图(而不是0/1)。
原标题:Using mysql with php and ajax, I want to print out a string (rather than a 0/1) for this query
  • 时间:2012-04-10 06:28:29
  •  标签:
  • php
  • mysql

如果这个问题在前面出现,我会抱歉,但我只想和发现只关心实际结果的人。

mysql_query($query);

I m 为用户能够创建数据库和通过与几个选定箱互动进行搜索的项目制作一个实验室/米斯克尔网页。 我也想能够简略地勾画出实验室生成的实际查询。

if($dArray[0] ==  sb2a ){
$sql = "SELECT * FROM Vehicles WHERE " . $dArray[1] . " =  " . $dArray[2] + " ";}
print($sql);

它只是印刷品0,而不是像材料一样。

“车辆号:WHERE VID = 1

Any help would be greatly appreciated.

问题回答

在您确定<代码>美元/<代码>价值的法典行文接近尾声:

. $dArray[2] + " ";

That + should be a .

if($dArray[0] ==  sb2a )
{
   $sql = "SELECT * FROM Vehicles WHERE " . $dArray[1] . " =  " . $dArray[2] . " ";
}
print($sql);

为了进行分类,我们应始终使用。

就像这一点一样。

$sql = "SELECT * FROM Vehicles WHERE {$dArray[1]}  =  {$dArray[2]} ";




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