Question

我也许会不正确地对待这一点,但我需要找到如何阻止 lo。页: 1 我有9个不同的声音。作为一个用户,我想要发挥不同的声望,使广度增加。此时此刻,每当游乐器点击 but子并投入工作时,我不会阻断已经起作用的音响。这些声音相互之间是公正的。

在用户向纽顿报到时,是否有办法关闭所有现有的声音?

在这里,我所倡导的法典是:

    public void playSound(){
    try {
        audio = AudioSystem.getAudioInputStream(soundFile[activeSound]);
        clip = AudioSystem.getClip();
        clip.open(audio);
        clip.start();
        clip.loop(Clip.LOOP_CONTINUOUSLY);           
    }

    catch (IOException ex){
        System.out.println("Sorry but there has been a problem reading your file.");
        ex.printStackTrace();
    }

    catch (UnsupportedAudioFileException ex1){
        System.out.println("Sorry but the audio file format you are using is not supported.");
        ex1.printStackTrace();
    }

    catch (LineUnavailableException ex2){
        System.out.println("Sorry but there are audio line problems.");
        ex2.printStackTrace();
    } 
}

两天前,我一直走到这里,我驾驶我。任何帮助都会受到高度赞赏。

Answer 1

你们想要的是停止一切现有的玩.。可使用)。你们都需要能够查阅所有现有的剪辑。以下是我的建议。请注意,我只用一字提及与目前停机坪连接。如果你不止一个,则使用<代码>ArrayList<Clip>而不是一个。

private Clip activeClip;
public void playSound(){
    activeClip.stop();
    try {
        audio = AudioSystem.getAudioInputStream(soundFile[activeSound]);
        clip = AudioSystem.getClip();
        clip.open(audio);
        clip.start();
        clip.loop(Clip.LOOP_CONTINUOUSLY);
        activeClip = clip;
    }

    catch (IOException ex){
        System.out.println("Sorry but there has been a problem reading your file.");
        ex.printStackTrace();
        }

    catch (UnsupportedAudioFileException ex1){
        System.out.println("Sorry but the audio file format you are using is not     supported.");
        ex1.printStackTrace();
    }

    catch (LineUnavailableException ex2){
        System.out.println("Sorry but there are audio line problems.");
        ex2.printStackTrace();
    } 
}

友情链接