Question

我建立了谷歌习俗搜索引擎,并利用吉大港山区理工学院启动询问。现在,谷歌正在恢复“JSON”模式的成果。我很想知道,如何将这名智者的产出纳入人类可读的方式。

例如:

Title: The matrix
htmlTitle: "The matrix.."

我看到,许多论坛都建议采用XStream办法。但不能确定我如何能够做到这一点。

请允许我帮助我。

仅供参考的是,我在此向《吉大港山区国际刑法》:

public static void main(String[] args) throws IOException {

    HttpGet httpget = new HttpGet("https://www.googleapis.com/customsearch/v1?key=AIzaSyBp_5Upf6h0QSXR8UveLs4_c6lAmGW_7B8&cx=014783642332862910131:opc1zgsvfhi&q=matrix&alt=json");
    System.out.println(httpget.getURI());
    ResponseHandler<String> responseHandler = new BasicResponseHandler();
    HttpClient httpClient = new DefaultHttpClient();
    String responseBody = httpClient.execute(httpget, responseHandler);
    System.out.println(responseBody);

Answer 1

首先,你需要创建一个等级,标明Goolge的对策,然后使用类似守则(:

String json = "{"product":{"name":"Banana","id":"123""
        + ","price":"23.0"}}";

XStream xstream = new XStream(new JettisonMappedXmlDriver());
xstream.alias("product", Product.class);
Product product = (Product)xstream.fromXML(json);
System.out.println(product.getName());

友情链接