Question

我推出一个方案,将拥有几个资源档案,用户可以把某些地方放在计算机上,该计算机的号码与可起诉的相同。我如何打开这些档案?

我找到了许多答案,说为什么事情没有奏效,就是说档案在工作目录中是一纸空文。我尝试提供完全合格的途径:

ifstream str;
str.open("/home/millere/foo.txt")

但未成功。我知道这条道路是正确的(范围和过去)。我无法找到这方面的任何文件,但我认为有必要这样做。 (vim ~/foo.txt 例如,从<代码>~以外的任何地方提取。

Answer 1

Assuming you meant to use ifstream instead of iostream, your code is correct. ifstream can use a path to a file as well as the name of a file in the working directory.

No exceptions are thrown if the file does not exist, but the fail bit is set. You should check for this before trying to do anything with the stream.

std::ifstream input("/home/bob/stuff.txt");

if (!input) std::cerr << "Could not open the file!" << std::endl;

else
{
    // ...
}

如果你仍然无法从档案中提取数据,问题在你的法典中是其他地方。

Answer 2

I had the same issue and quickly noticed that, open when trying to get from a difference folder, had a different source directory (if using Cmake, the one that was specified by the cmake). You can find out, what the ouput/input source directory is by doing

system("ls")

或

system("dir")

显示现有数据/投入目录内容的窗口。

友情链接