Question

我难以确定如何将我的分歧机器人编成密码,以明确某个特定用户(ex./purge [user] [num]的信息。我已经能够从总体上明确信息,但能够把问题与具体用户联系起来。我是新 brand,因此,我们非常赞赏任何帮助。

感谢!

#Purge command
@commands.has_permissions(administrator=True)
@bot.slash_command(
  name="purge", description="Purge messages from channel", 
  guild_ids=[1222114873962663967]
)
async def purge(ctx, number: int):
  await ctx.channel.purge(limit=number+1)
  await ctx.respond(f"Purged {number} messages")

该法典对打造电文做了罚款,但我对如何用任择的“用户”参数加以编码感到损失。

Answer 1

TextChannel.purge() 方法还有<代码>check参数,通过该参数,你可以召集一个功能,过滤将删除的信息。例如:

#Purge command
@commands.has_permissions(administrator=True)
@bot.slash_command(
  name="purge", description="Purge messages from channel", 
  guild_ids=[1222114873962663967]
)
async def purge(ctx, number: int, member: discord.Member = None):
  if member:
    deleted = await ctx.channel.purge(limit=number+1, check=lambda m: m.author == member)
  else:
    deleted = await ctx.channel.purge(limit=number+1)
  await ctx.respond(f"Purged {len(deleted)} messages")

Answer 2

You can loop through channel.history and check if the message.author is the one you specified with member which is of type discord.Member. If a member is provided it will only delete the messages from the member, otherwise all messages.

#Purge command
@commands.has_permissions(administrator=True)
@bot.slash_command(
  name="purge", description="Purge messages from channel", 
  guild_ids=[1222114873962663967]
)
async def purge(ctx, number: int, member: discord.Member=None):
  if member is not None:
     async for message in ctx.channel.history(limit=number):
        if message.author == member:
           await message.delete()
     return
  await ctx.channel.purge(limit=number+1)
  await ctx.respond(f"Purged {number} messages")

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