Question

I m trying to sort a map in Groovy that has maps as value. I want to iterate over the map and print out the values sorted by lastName and firstName values. So in the following example:

def m = 
[1:[firstName: John , lastName: Smith , email: [email protected] ], 
2:[firstName: Amy ,  lastName: Madigan , email: [email protected] ], 
3:[firstName: Lucy , lastName: B ,      email: [email protected] ], 
4:[firstName: Ella , lastName: B ,      email: [email protected] ], 
5:[firstName: Pete , lastName: Dog ,    email: [email protected] ]]

预期成果是:

[firstName: Ella , lastName: B ,      email: [email protected] ]
[firstName: Lucy , lastName: B ,      email: [email protected] ]
[firstName: Pete , lastName: Dog ,    email: [email protected] ]
[firstName: Amy ,  lastName: Madigan , email: [email protected] ]
[firstName: John , lastName: Smith , email: [email protected] ]

I ve Trial m.sort{it. Value.lastName&&it. Value.firstName} and m.sort{[it. Value.lastName, it Value.firstName]}. 由m.sort{it. Value.lastName}进行职业介绍,但不是按Name进行。

任何人都能够为此提供帮助,我们非常赞赏、感谢!

Answer 1

应:

m.values().sort { a, b ->
  a.lastName <=> b.lastName ?: a.firstName <=> b.firstName
}

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