Static Data

Question

timeline.js + MVC + Ajax + JSON

hello,

我在把扼杀变为Json目标时有问题。

我不得不在我的网页上展示时间表,我使用了时间线。 j 同样,我能够利用静态数据操作时间表,数据如下:

Static Data

// Create a JSON data table
data = [
{
         start : new Date(2010, 7, 23),
     content :  Conversation 
},
{
     start : new Date(2010, 7, 23),
     content :  New Conversation 
},
{
     start : new Date(2010, 7, 23),
     content :  Very New Conversation 
}

我现在发言。

alert(data);

我

[object Object],[object Object],[object Object]

但现在我必须显示亚洲开发银行的数据,因此,我要求履行以下关于控制员的职能。

GetTimeLine method on controller

public JsonResult GetTimeline()
{
      JsonResult jr = new JsonResult();
      var objtimeline = objEntities.Timelines.Where(tl => tl.StudentID == Sessions.StudentID).ToList().AsQueryable();
      String newstr = "[";
      foreach(var tml in objtimeline)
      {
            DateTime date1 = Convert.ToDateTime(tml.CalculatedDate);
            newstr += "{ start : new  Date("+date1.Year+","+date1.Month+","+date1.Day+","+date1.Hour+","+date1.Minute+","+date1.Second+"), content : "+tml.Description+" },";
      }
      newstr = newstr.TrimEnd( , );
      newstr += "];";
      jr.Data = newstr;
      jr.JsonRequestBehavior = JsonRequestBehavior.AllowGet;
      return jr;
}

function to call controller method

jQuery.ajax({
    type: "POST",
    url: "@Url.Content("~/Student/GetTimeline")",
    success: function (result) {
        data = result;
    },
});
alert(data);

我 the following alert

[{ start : new Date(2012,2,11,0,0,0), content : Parents meeting },{ start : new Date(2012,2,15,0,0,0), content : Exam Meeting }];

因此,问题在于将扼杀物改为Json物体,

我认为,我怎么能够把从控制员返回的扼杀改成Json物体。

Answer 1

你的工作太困难。让框架为你们服务。

public JsonResult GetTimeline()
{
     var timeline = objEntities.TimeLines.Where( tl => tl.StudentID == Sessions.StudentID )
                                         .ToList() //required due to Convert call
                                         .Select( tl => new
                                          {
                                               start = Convert.ToDateTime(tl.CalculatedDate),
                                               content = tl.Description
                                          });
     return Json( timeline, JsonRequestBehavior.AllowGet );
}

然后使用<条码>。 (因为你特别允许查阅)或具体规定<代码>数据表:json 。

$.getJSON(  @Url.Action("gettimeline","student") , function(data) {
     alert(data);
});

Answer 2

您的服务器返回并不有效。或者给你的服务器方代码,这或许是有效的。 In JSON:

All object keys must be in double quotes, not single quotes.
All strings must be in double quotes, not single quotes.
new Date(...) is not valid (JSON doesn t have any concept of dates).

我认为,你希望建立一个阵列(而不是一个阵列),并将之分配到<条码>jr.Data,然后让 >bject<。处理您的序列化(但我没有在ASP.net MVC中这样做)。

Once you have the server returning valid JSON, ensure that it s returning it with the correct Content-Type header (the value is application/json). When you do, jQuery will see that it s JSON and deserialize it into an object graph for you. If you can t or don t want to make your server return valid JSON, add dataType: json to the ajax call to force it.

Static Data

GetTimeLine method on controller

function to call controller method

友情链接