Question

是否有可能将两种图像与不同的决议相比较?

我这里指的是一些算法/方案拟订方法。例如,现在,我计算出hash代码,从图像外围阵列,并比较这些散列代码数值。这是一项巨大的工作,但在不同的决议中却失败了,即:图像是相同的bywatch,但其内容不一样。

For example see my image attaches:
enter image description here

其中一个网站72 ppi,但另一个网站96 ppi。在对平等进行比较时,我想有TRUE值,但现在我获得<>FALSE。请在此找到正确的解决办法。

Answer 1

Two very simple perceptual hashing methods you might give a try before venturing into more complicated territory are based on the Discrete Cosine Transform and the local vs glocal mean of an image:

图像转换为光电

1.1(EDIT) 塑造你的形象
Crush your image down to thumbnail size, say [32x32]
Run the two dimensional Discrete Cosine Transform
Keep the top left [8 x 8], most significant low frequency components
Binarize the block, based on the sign of the components
Result is a 64 bit hash

关于这一主题的备选案文是

图像转换为光电
Optionally re-size to a predefined size.
Partition the image in a fixed number of blocks
Determine the global mean
Determine the local mean per block
For the hash, write out a 1 or a 0 per block, pending if the local mean was larger or smaller than the global mean.

另见。

Answer 2

对于有几张不同颜色的合成图像,我首先要用自己的图相配。

基本上将每张颜色的颜色数量乘以图象总数。然后,你有简单的浮质,作为inger。如果你希望有更多或更少边界的图像能够算作匹配,你就可以忽视白人。

It s not going to detect the same image with the slices re-arranged, or the text moved down a line but i don t think that is the concern in this case

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