Question

我们有这样的要求,即我们希望从同样的申请中公开多个网站概览。

E.g Android app1 should open page1.html in first webview instance and page2.html in second webview instance. When page2.html is started page1.html webview should go in background.

是否可在安乐斯这样做? 是的,请提供样本代码或链接,详细说明如何满足这一要求。

Answer 1

public void callwebtwo(){
            loadweb = (WebView) findViewById(R.id.loadweb);
            loadweb2 = (WebView) findViewById(R.id.loadweb2);
            loadweb2.getSettings().setJavaScriptEnabled(true);
            loadweb.getSettings().setJavaScriptEnabled(true);
            loadweb2.loadUrl("http://www.google.co.in/");
            loadweb.setWebViewClient(new WebViewClient() {
                @Override
                public boolean shouldOverrideUrlLoading(WebView view, String url) {
                    Log.i("shouldOverrideUrlLoading", url.toString());
                    return super.shouldOverrideUrlLoading(view, url);
                }

                @Override
                public void onPageFinished(WebView view, String url) {
                    Log.i("onPageFinished", url.toString());
                    super.onPageFinished(view, url);
                }

                @Override
                public void onPageStarted(WebView view, String url, Bitmap favicon) {
                    Log.i("onPageStarted", url.toString());
                    super.onPageStarted(view, url, favicon);
                }

                }

            });
            loadweb2.setWebViewClient(new WebViewClient() {
                @Override
                public boolean shouldOverrideUrlLoading(WebView view, String url) {
                    Log.i("shouldOverrideUrlLoading", url.toString());
                    return super.shouldOverrideUrlLoading(view, url);
                }

                @Override
                public void onPageFinished(WebView view, String url) {
                    Log.i("onPageFinished", url.toString());
                    super.onPageFinished(view, url);
                }

                @Override
                public void onPageStarted(WebView view, String url, Bitmap favicon) {
                    Log.i("onPageStarted", url.toString());
                    super.onPageStarted(view, url, favicon);
                }



            });

}

instance of the both web is different so it will work and perform seperatly.. i gvn ans whtever i cn understand frm ur quest.

Answer 2

是的。

在二次网上调查中,当你装满第2页时,就会为二次,而当你从第2页回击时,第1页就会是冒犯的。

友情链接