Question

我对财产及其价值进行了描述:

str = "filter: progid:DXImageTransform.Microsoft.gradient(startColorstr= #cccccc , endColorstr= #000000 );
       background: -webkit-linear-gradient(top, black, white);
       animation-duration: 12s;";

我只希望归还财产。

properties = text.match(/[^;:]*:/g);

但它也回报了“progid:”我如何避免?

Answer 1

• 探寻线的开始或“;”以及(或视你的铺设格式,视可能划线/划线):

/(^|;)[^:;]*:/

不过,你仍然只能清理结果。

或者,你可以把“;”一分为二,然后按“:”和将每一成员的0位成员 gr为主:

var str = "filter: progid:DXImageTransform.Microsoft.gradient(startColorstr= #cccccc , endColorstr= #000000 );background: -webkit-linear-gradient(top, black, white);animation-duration: 12s;";

var rules = str.split(";")

var i, l = rules.length;

var properties = [];

for( i = 0; i < l; i++ ){
    properties.push( rules[ i ].split(":")[0] ); //dangerous if you re not sure you ll always have a result
}

Answer 2

请审判

properties = text.match(/^[^;:]*:/g);

EDIT: Here is a better solution provided there is always a space between property and value:

properties = text.match(/[^ ;:]+(?=: )/g)

Answer 3

避免在你分裂成半途而结束扼杀的空洞规则,

split on semis with content following them;

var rules= str.split(/;(?=S+)/);

for(var i= 0, L= rules.length; i<L; i++){
    rules[i]= rules[i].split( : )[0];   
}

/* 
alert(rules)>>(Array)
filter, background, animation-duration
*/

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